#Cant Solve This
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Can you show what you've tried?
Well, I mean your attempt at a solution.
The first screenshot is my attempt.
Theres not much else I can do.
Using Desmos is not your attempt.
Please try it yourself.
My professor does not teach us how to solve it ourselves rather having us use technology. Her words not mine ¯_(ツ)_/¯
Well, do you know the usual process of bringing a system to RREF?
Just usual Gauss' method.
Im familiar with it as the "show me an example" shows the process.
Alright. If you're familiar with it, try it.
I guarantee you, that it is not the right answer.
I tried that ;-;
Well with the other variations of the same problem, the answer is not that.
Its definitely not expecting it.
that is not possible
the system you start with has rank 3
no matter how you fill this out, it's rank 4
¯_(ツ)_/¯
Screencap the problem and send it to your instructor with the remark: technology disagrees
at any rate, the parametrised solution is this
I did it ONE time and got the right solution but that was a one time thing 
if you do it correctly you'll get it right every time
I did it exactly the same way every time
One time somehow it was right then the rest was wrong.
if you are expected to change rank 3 into rank 4, then that's not possible
Heres the system of equations based on the problem
Here's what I got. Everything seems to be fine.
and its augmented matrix
Hey, spoilers! 😅
Dont worry, it's not what was expected anyway because technology disagrees.
The calculator agrees with your solution but not with the problem.
yes and I already checked the rref you found is correct
What do you mean? I got the same result as Desmos.
The question itself disagrees.
Because the problem itself is wrong.
How so?
Scroll thru the thread.
The question disagrees with the template for answering.
Oh, is it supposed to have a unique solution?
it can't 
In that case yeah, the problem isn't set up correctly.
That's fine, it happens.
Although, that just means there are infinitely many solutions with one degree of freedom.
@rancid ridgewrite to your course supervisor
That also works, I guess.
assuming this is homework or some such
As w, x, y, z need to all be nonnegative, we have {w, x, y, z} = {t, 75 - t, 40 - t, t} for 0 ≤ t ≤ 40.
this is the entire problem and how its wrong and such.
I suggest you also post your attempt, so that the teacher at least knows that you've also tried it.
What's this?
This
Oh. Well, yeah.
As we discussed above, we get {w, x, y, z} = {t, 75 - t, 40 - t, t}.
yes thats what I got too
so what's the problem
I didnt say there was
Well, I assume the problem wanted a unique solution. Guess it wasn't set up correctly.
let's just solve the problem as stated, not start speculating
Oh, we already did.
Im creating a thread in the class. So everyone is aware of it and they don't go crazy as I did 🙏
Okay, to anyone who is still here and willing to help
Can someone explain this problem to me.
How does one get the system of equations? Why is the answer D) ?
Hm...
Well, we can take x + y as 3 and multiply it by 8 at the top. Not sure why 3x + 2y has to be 8 at the same time, though.
Why x+y as 3?
I kinda understand 3x+2y=8 (from the game card)
Then we can make 24 as 3*8.
What I don't really get is why 3x + 2y has to be 8 at the same time, though.
I thought that too but clearly its not right
Because of this
Am i just being given weird problems lol
Yeah, this one is a bit weird, to be honest.
We have to make use of all 4 numbers, namely 8, 9, x+y and 3x+2y, to form 24 algebraically
In addition, x and y are constrained to be single-digit positive integers
For part (a), it can be conveniently observed that options A and C fail the constraints on x and y by subtracting both sides among the equations
For the second parts of each a and b i did this
I wrote code to solve it in order to speed up the process. (obviously wont be done in exams and such)
Ohh, we have to use all of them. I see.
similarly, by observing the difference between equations for option B, x must be 1 and y must be 2, which contradicts with either equation.
This I understood.
How do we make 24 from 3, 8, 8 and 9, though?
3*(9-8/8)
hence testOne
Ohh, I see.
I've never been good at problems like these, to be honest...
I don't really like problems where brute force is the only way.
But how do i even get 3 for the first equation. x+y=3
We draw a random quadruple of poker cards and play with them
Like how do i know for sure which system of equation is the right one.
You just check the solution sets for violations of the given constraints
Could you visually represent this?
Im still slightly confused.
For A, 2x+y = 1, but x and y must be positive integers so the sum should be at least 3
Similarly for C
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