#I need to calculate the value of the c_1 and c_2 (following theses conditions, y(-1)=0, y(π)=0)
elder bearBOT
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close
- Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
tall belfry
the values of c_1 and c_2 are (1,-1) but idk how my teacher get there
pallid saffron
You have:
y = (C1 cos(x) + C2 sin(x))e^x
Susbtitute the given boundary conditions. You will get a system of two equations in C1 and C2.
tall belfry
You have:
y = (C1 cos(x) + C2 sin(x))e^x
Susbtitute the given boundary condition...
idk how to do it that way, the way my teacher told us is to change with the solution equation the Initial conditions, but when i do that idk how to continue the exercise
pallid saffron
idk how to do it that way, the way my teacher told us is to change with the solu...
We have y = (C1 cos(x) + C2 sin(x))e^x
Substitute x = -1. What do you get?
tall belfry
We have y = (C1 cos(x) + C2 sin(x))e^x
Substitute x = -1. What do you get?
mmm if we subsitute y(-1)=(c_1 Cos(-1) + C_2 Sin(-1))e^-1
y(-1)= (c_1(0.54)+C_2(0.84))(0.37)
am i doing it well or wrong?