Can someone please help me out with this question?

[gusty eagle]

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[dawn wolf]

thoughts? attempts?

[past mulch]

just a second

[dawn wolf]

what's going on in the second picture?

why are you equating b+c = 0?

[past mulch]

we cant cancel that out right?

[dawn wolf]

both b and c appear in logarithms

so they must be positive numbers

where does this come from?

[past mulch]

i substitued for logs a variable

[dawn wolf]

so you get it from this equality?

[past mulch]

yes

[dawn wolf]

how does this turn into summation, then?

[past mulch]

substituted in the third eq

[dawn wolf]

what is the third eq?

[dawn wolf]

for the record, you correctly deduced that

$$ (\ln 2)(\ln b) = (\ln a)(\ln c) $$

[verbal bronze]

aL

[dawn wolf]

$$ 6a = 3\cdot 2a = 3\left((2a)^{\ln a}\right)^{1/\ln a} $$

[verbal bronze]

aL

[dawn wolf]

is what I would try

@past mulch

I don't see how you conclude the bottom equality here from the substitution

[past mulch]

+close