#integration problem

33 messages · Page 1 of 1 (latest)

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molten sonnet
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I don't really see a differential.
Can you provide some context? I'm not sure if you wrote the integral correctly.

late dagger
molten sonnet
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Still no differential. And no context.

late dagger
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sorry. my question is how the delta x effects the resoult

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the diffrence is absenco of delta x in the second pic

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i want to make a sum of t in interal x to zero

molten sonnet
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What's that letter on the left?

late dagger
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but i dont know how to put the delta x in calc

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t

molten sonnet
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So, is this what we have?
t = lpxΔx/(λΔT)

late dagger
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yes

molten sonnet
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Hm. And you want to integrate it with respect to what variable?

late dagger
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x

molten sonnet
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Well, alright.
Are l, p, Δx, λ and ΔT constants?

late dagger
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yes

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well Δx is limit to zero

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is that a constant

molten sonnet
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Alright. In that case:
∫(tdx', 0, x) = (lpΔx/(λΔT))∫(x'dx', 0, x) = lpx^2 Δx/(2λΔT)

molten sonnet
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Again, I think you are not interpreting whatever you're trying to solve correctly.

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Where did this quantity come from?

late dagger
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you mean that equation?

molten sonnet
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Yes.

late dagger
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where Q is ml=SΔxpl

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and this t

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d becomes x

molten sonnet
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Hm. Looks familiar.
Are you sure that t and τ denote the same quantity, though?

late dagger
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yes

molten sonnet
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Hm... Still not sure what needs to be done, to be honest.

late dagger
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if the delta x is limit to zero is the result of integer 0