#Can I please get an answer to this question?

20 messages · Page 1 of 1 (latest)

silent rose
weak turtleBOT
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feral bane
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here is a proof

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in your case n = 1998

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@silent rose

silent rose
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n is 43 right?

feral bane
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what makes you say that?

silent rose
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oh i am sorry. my apologies. but without formula how do we do it?

feral bane
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you can always add them up by hand

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but that's tedious if you have 1998 terms

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or write a quick for loop that does it for you

silent rose
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yeah...can i know the answer to this because when i calculated i got 58586?

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the way i solved it was
[√1] = 1
[√2] = 1
[√3] = 1
[√4] = 2
[√5] = 2
[√6] = 2
...
[√8] = 2
[√9] = 3
[√10] = 3
...
[√16] = 4
...

feral bane
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$$ 44 \cdot \left( 1998 - \frac{(2\cdot 44+5)(44-1)}{6}\right) = 58, 586 $$

kindred oracleBOT
feral bane
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that's also what I get

silent rose
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thank you so much .....you're a lifesaver. i have been stuck with this problem since morning..thank you

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+close