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#related rates calculus
rustic flame
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azure badger
This is how I'd do it, not sure if it's the standard approach
Calculate the length of the arc as a function of k
Set k = k(t) because k isn't an independent variable in this case due to "k increases at a rate of 3 units per second" (we are creating a new time variable). Notice then that k'(t) = 3 always
Differentiate the expression of the arc with respect to t and replace k'(t) with its value (3) and k(t) with 5 because they asked for when k=5.
rustic flame
This is how I'd do it, not sure if it's the standard approach
Calculate the len...
u online bro ?
Lil Blud is stuck
weak plinth
help
Let's see. We have:
dl = √(1 + (dy/dx)^2)dx = √(1 + (dy/dx)^2)(dx/dt)dt
So:
dl/dt = √(1 + (dy/dx)^2)(dx/dt)
You know y and dx/dt, so find dy/dx and substitute k = 3, x = 5.
rustic flame
Let's see. We have:
dl = √(1 + (dy/dx)^2)dx = √(1 + (dy/dx)^2)(dx/dt)dt
So:
dl/d...
Where did you get dl
I mean dx/dt
It should only be sqrt(1 + (dy/dx)^2)
