#percentage change
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If the initial sum is N0 and each year it changes by a fraction p, then the sum at year n is:
N(n) = N0 (1 + p)^n
I’ve never learnt it that way before 😭
Really? Huh, that's odd.
Yeah it’s killing me I have my exam tmo and this is 100 percent coming up I have no idea what to do lmao
Well, calculate N(12).
From the method I use I got £9250.35 but online it’s saying he owes like £5383.08
Well, I agree with the first. Not sure how the resource you found calculates it.
I emailed my maths teacher about it like 5 minutes ago and he just replied saying that I got it right so I’m just going to completely ignore whatever it said on safari 😭
Oh. Well, nice!
100%+24% = 124%\100 = 1.24 700x1.24^12 = £9250.35