How do you do this (I kinda know but I need some like guidance)

[solar hare]

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[broken ledge]

Well, you get two solutions:

x1

x2

[limpid copper]

okay I'm gonna sound really stupid right now but in my caculator I got -14 and -20

[broken ledge]

lemme calculate

its

no

[limpid copper]

where did the 93 come from

😭

[umbral bobcat]

Giovyx

[broken ledge]

4ac

4ac

[limpid copper]

is this a parabala question

no

[broken ledge]

It is a quadratic equation, so it has 2 solutions. since b is 3, b^2 is 9.

-4 * 3 * (-7)

which is the delta

[limpid copper]

OOOH

I wasn't doing um... -7

I was doing 7

[broken ledge]

so, after that, you calculate the sqrt with a calculator

and you round to whatever

[limpid copper]

sorry ill be a few minutes but why do you square root

[broken ledge]

I mean, you could look at the proof of the quadratic formula

its some completing square staff

[limpid copper]

I donh't have time for all that

I got 8 and 14

but i need to go

is it both of them

ill @ u in like 10 mins or something

is that okay

[broken ledge]

Yes, but i didn't get 8 and 14

i got 1,1 and -2,1

[broken ledge]

sure

[willow ruin]

this isn't correct

[limpid copper]

im back

@broken ledge

[willow ruin]

i don't know anything about quadratic equations

[willow ruin]

please anyone tell what I did

[broken ledge]

It's correct, but its not effective to solve what we doing

[broken ledge]

@limpid copper

[willow ruin]

ok

[limpid copper]

how did you get coords

[broken ledge]

i did sqrt with a calculator

and did basic math

[limpid copper]

why do you do square root

[broken ledge]

because 93 is under sqrt

[limpid copper]

I don't know how you got 93

[broken ledge]

sure

$\sqrt{3^2-4(3)(-7)}$

[umbral bobcat]

Giovyx

[limpid copper]

why would it be 93 and not just 9

[broken ledge]

9-12(-7)

-12x(-7)=84
9+84=93

[limpid copper]

then how did you get coords

[broken ledge]

there's no coords

just to find x

[limpid copper]

you said 2,1

or

[broken ledge]

decimal

[limpid copper]

1,1

[broken ledge]

2,1 and 1,1

[limpid copper]

then use a .

not a ,

[broken ledge]

We use ,

[limpid copper]

theres a difference

what do you use for coords

[broken ledge]

A(1;1)

[limpid copper]

well then

[broken ledge]

. is more correct

[limpid copper]

how did you get 1.1 and -2.1

[broken ledge]

solved these

[limpid copper]

what was the full version of those

[limpid copper]

I'm still just getting 14

if I put that in

anyway

it doesn't matter

I emailed my teacher

so you don't need to help me anymore

[willow ruin]

can't it be solved by the quadratic formula

[limpid copper]

thats what we've been discussing for 45 minutes

doesn't matter