A body weighing 95 grams is shot vertically upwards at a speed of 37 meters per second.
A. Calculate his speed at a height of 15 meters above the ground if it is known that by the time he reached this height he had lost 12 joules of mechanical energy as a result of smiling with the air.
B. It is known that during its entire movement from the ground to the peak height reached by the body, 28 Joules of the mechanical energy were converted into heat energy. Calculate the maximum height the body reached.
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What do you need help with @dusk grove
Anything you don't understand
and most important whats the answer
work energy+ projectile motion should help
you can calculate its kinetic energy at time of projection
Initially, Kinetic energy= total mechanical energy=65joules
$k=$65
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When it is at a height 15m, its total mechanical energy,
is 65-12(lost by air)=53J
since it is at height 15m it has some potential energy
$u=$mgh
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Calculating, U=14.25J
Since total mechanical energy= K+U,
We have K at 15m= 53-14.25
K=38.75 at 15m
now $k=$1/2mv^2
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m won't change (mass), we have equation of speed as $v^2=$2k/m
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$v^2=$818
After doing the calculation you will get $v=$28.6,
Approximations made:
i)65.02J as 65J
ii)g=10m/s^2
iii)817.8m/s^2=818m/s^2
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