#Linear Algebra - Eigenstuff

1 messages · Page 1 of 1 (latest)

novel tulip
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Not sure what to do beyond the deduce V = U + W bit

wild pivotBOT
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novel cedar
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eigenvectors corresponding to distinct eigenvalues are linearly independent

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so U interset W = {0}

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provided that both +1 and -1 are eigenvalues

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if you take bases of the eigenspaces and put them together, you get a basis for V (because U direct sum W = V)

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matrix is diagonalisable iff V has a basis of eigenvectors

novel cedar
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@novel tulip

novel tulip
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ive got it thank you

novel tulip
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+close