#I can't make graphs
172 messages · Page 1 of 1 (latest)
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The easiest way is to pick two values for x and solve the equation... some values of x are easier to solve than others, depending on the equation
If you pick 0 for your first value of x, then solve, you'll have the matching y coordinate... for that equation, you'll want to multiply 4 against something that will make a product that divides by 5 nicely
Depending on how picky your teacher is, whole numbers are usually easier to graph than fractional coordinates
So if m= 4/5 then x=5 (4/5×5=4)?
but you also need to consider the b part
so like
you have a point, when x=5, your y is equal to
something specific
Yep... then like random said, complete the rest of the equation, and you're left with y = something
So your second point will be (5, something)
Why do you feel like that?
5,2 is a point on the line yea
use desmos
you can replace the x and y with the respective
guys what are we talking about
$1=\frac45 \times 5 - 3\\1=4-3$
I used desmos first and every time it said the answers were wrong
!𒐪 ɹɐupoɯ⇂ㄥ8𝟝 𒐪!
what is the question lol
meh just rise/run it
Translating the words into math that I can understand isn't going so well
count squares
f(x)=3/5x-7
It's wrong
Yes
I'm trying to graph it
The blue line is wrong and the answer desmos gave me wasn't an option because the graph doesn't go that far but now the thing just says it's wrong
okay you might want to understand how slope works
so the top number is how many tiles the y value changes per the bottom number, how many tiles the x value changes
I wonder if Reid has heard "rise over run"
oh ye
That's another way to get your second point
Looks like we switched equations while I was sketching
The one I gave was the original question but it reset to make sure I'm not cheating
Ok
So far I can identify the different parts of the equation and make it into different forms it's just understanding how the slope applies to the graph is where I'm stuck
rise over run
y/x=3/5 so move the second point to (5,3)?
You can either use the simple counting method that random mentioned... your slope is 3/5, so count up 3 (because your slope is positive) and right 5, or pick a new number and repeat the process
Okay
It looks like you might be counting them backwards.. look at the change in y value (rise) compared to the change in x value (run) in the correct answer
See how they're backwards from your answer?
Yeah I see it
I'm getting closer. Mine went through (3,0) but it should've been (6,0)
I finally got one
Mark at the y-intercept
Go across x and up y
Makes sense now but I kept getting confused over the slope
Where are you getting your x and y values to go across and up?
The question was y=4/5x-6 so from (0,-6) I went across 5 and up 4 which gave me (-5,-2) I think. It moved to the next question so I can't see for sure
5?
Yep... are you sure you got (-5, -2)?
Not completely
So.. let's try this...
Starting from the origin (0, 0) you've got a line that passes through the point (3, 7)
What's the slope?
7/3
Awesome
So let's say your equation is:
y = 7/3x + 4
Where does the line intercept the y-axis?
b=4
3 for 3... so I'm honestly confused on how you're not getting the correct answers on your homework!
Seems like you understand it well enough
Because I always focused more on the equations and half assed my way through graphs
On your homework, do you have some scratch paper next to you so you can graph the points out, draw the line, and then answer the question?
Or are you trying to just look at the screen and answer it?
I'm using my iPad for scratch working it out and answering on my computer
It's moved on to undefined graphs
So you're starting to get the correct answers? Or.. you're just moving on?
And who keeps doing that??!
gift heart weirdness
You helped with me 6, I knew how to answer 7, and now I'm stuck on 8. I know it's vertical and doesn't have a function but I don't know how to translate that into my computers graph.
Ah, ok... so how would you graph a flat, horizontal line?
Something parallel to the x-axis, where the y value never changes
Straight across through y
And what would the formula for that look like?
I'm not sure
y=z, No x
Nope
Worth a shot
Heh...
It's just y = 3
Or whatever your y-intercept is
y always equals that number, no matter what
even if x changes, y always = 3
So now... if you have a vertical line, x always equals the same value, right?
In this case x=8
It requires me to make a line
I think the last walk through used (x,0) and (x,1) so ig it'll be (8,0), (8,1)
Got it
No desmos kept giving me the wrong answer
I used to wish for homework but now I never want to see it again
OHHHH....
That might be your problem, yep
In fact, that is exactly your problem... you've been giving it the inverse function
Which is why your slope was backwards
Of course 😑
Hey, at least it's an easy fix!
Yup
I just put in my notes that the slope is relative to b which makes sense since b is a constant and the slope uses a variable
Slope doesn't use a variable
y=mx+b?
No... y is also affected
Ughhhh
That's why you get a new y value for every x value you plug in
Okay
So b is constant, everything is touched by x, m is slope, don't do it backwards.
Because functions?
b is constant, and for your purpose right now, m is constant
The slope of a straight line never changes, right?
it's always 3/5 or whatever
We're just multiplying the slope m by the x coordinate we want more information about in order to obtain the corresponding y value
Because functions 😉
I can't wait to get back to pre-calc I'm already tired of graphs
It's moved on to making a graph after switching around the numbers to slope intercept form
Feels like I'm close tho
heads up... in pre-calc, your slopes are going to start changing based on the value of x
So what I'm doing now will be considered backwards for pre-calc?
I wonder if it's too late to drop out /j
This is a simple graph of the sin function... as you move along the x axis, the slope changes.. sometimes positive, sometimes negative, etc.
Heh... yeah, it can get rough
But for your straight lines, for now, consider slope (m) to be constant
At least it's thorough ig