#trig equations
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put tan^2=sec^2-1
and solve the quadratic
but answer should be more than 1 or less -1
@warped zenith
Goose
sub sec\theta for u:
\newline
\newline
$3u^2+4u-4=0$
Goose
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Goose
The following error occured while calculating:
Error: Unexpected type of argument in function pow (expected: number or Complex or BigNumber or Fraction or Unit or Array or Matrix or string or boolean, actual: function, index: 0)
okay what now
well arcsec 2/3 is not defined
and arcsec(-2) has 2 values of theta
$2\pi/3$ and $4\pi/3$
scilent
yeah i got that far
i mean i forget what i add to the values when its arcsec
like the quadrants
if you know what i mean
you mean like sign?
yeah
dont these questions have
the theta values +90, +180 or +360
ahh right
+180 because of the range
oh right
that too
so 6 answers
got it
thank you so much
these 2
thats it?
just verifying i got the right answers:
\newline
$2\pi/3$
\newline
$2\pi/3 +180$
\newline
$180-2\pi/3$
\newline
$4\pi/3$
\newline
$4\pi/3+180$
\newline
$180-4\pi/3$
Goose
2pi/3 + 180 is more than 360
scilent
thanks very much
@warped zenith has given 1 rep to @hushed field
+close