hard question in korea

[languid condor]

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[bleak hill]

yo

let me try

$loga = 2(loga- \floor{loga}) + log2a - \floor{log2a}$

[vagrant robin]

Gary

[bleak hill]

$0 = loga- 2\floor{loga} + log2a - \floor{log2a}$

[vagrant robin]

Gary

[bleak hill]

$\floor{log2a} + 2\floor{loga} = loga + log2a$

[vagrant robin]

Gary

[bleak hill]

$\floor{log2a} + 2\floor{loga} = log2a^{2}$

[vagrant robin]

Gary

[bleak hill]

$\floor{log2a} + 2\floor{loga} = 2log2a$

[vagrant robin]

Gary

[merry matrix]

bro 2 log a

[merry matrix]

bro log 2a³

[merry matrix]

bro thats just wrong

[bleak hill]

what where

how

[merry matrix]

how is log 2a²=2log2a

[bleak hill]

oh f

yeh

🗿

[merry matrix]

and you missed a 2

[bleak hill]

skill issues

yeh

i did

[merry matrix]

like 3 steps ago

[bleak hill]

which 2

[merry matrix]

2loga - 2[loga]

oh wait

nvm mb

[bleak hill]

yeh it cancel out

[merry matrix]

is the answer 500?

[tardy moon]

correct

howw the

wow

[merry matrix]

its kinda lengthy

[merry matrix]

put loga = I+f here where I is an integer and f is between 0 and 1

[tardy moon]

ye yeeyeye

wait do you do korean math?

[merry matrix]

what the hell is korean math

[bleak hill]

$\floor{log2a} - log2a^{2} + 2\floor{loga} = 0\
\floor{log2a - log2a^{2}} + 2\floor{loga} = 0\
\floor{log\frac{1}{a}} + 2\floor{loga} = 0\ \$

lmfao

[vagrant robin]

Gary

[bleak hill]

anyways

i was thinkin smt like this

log 1/a will be negative or both log 1/a and log a become zero

[merry matrix]

i solved it bro