#Need help to make quadratic equation

18 messages · Page 1 of 1 (latest)

frigid patrol
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Two water taps together can fill a tank in 9$\frac{3}{8}$ hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time(in hrs.) in which tap of smaller diameter can separately fill the tank

gilded windBOT
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abstract shuttleBOT
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Infinite

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burnt glade
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@frigid patrol

frigid patrol
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How?

burnt glade
frigid patrol
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How 1/a and 1/b? , that's my doubt .

jovial narwhal
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two taps fill the tank in 9$\frac{3}{8}$ hours
tap a: fills it with $\frac{1}{a}$ per hour
tap b: fills it with $\frac{1}{b}$ per hour
In other words:

  1. Equation: 9$\frac{3}{8}$ * $\frac{1}{a}$ + 9$\frac{3}{8}$ * $\frac{1}{b}$ = 1
    Since tap a is 10 hours faster than tap b
  2. Equation: a = b - 10
abstract shuttleBOT
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muerte

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jovial narwhal
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You can simplify from there, no?

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(sorry, I am not used to using latex)

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Now just insert equation 2 into equation 1

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and you can solve for b

burnt glade
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\times is nice

burnt glade
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so if one takes like idk 5 hours to fill up the tank