#please help me thank you
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what did they teach in class?
I have no idea I'm sorry
i couldn't focus during class
but they said solve it with your own formula?
you must have some class material
there's a lot of way to do something
@glacial bolt try it
I don't know how to help him
awoop
are direct answers allowed? no?
Nope
uh oh
Do you know how to solve tho ? Or just answer
use these 2 theorems
oh thank you I will try
i can't do it I'm sorry i don't know how
Ok let's see the 1st one
Let's take intersection point as P
And focus on first theorem from this
We can take distance 5 as A, distance 5+8 as B, distance 6 as C and 6+x as D ?
I wanted to write points but not on pc atm
Well anyways, from this we know PA, PB, PC and we gotta find PD
@near lily can you do it now ๐
It's ok it's ok
i don't understand at all
Yes sir
Oh yes yes
yes
To what ๐
But where did you get 29?
Ohh
I took +6 on other side
It was 6+x = 65/6
x = (65/6) -6
x = (65-36)/6
Okie now next question
Wait what
Also don't you think next theorem is just the same 
So the answer is 6?
Nah
Oh
It's 29/6
oh my
Which would be almost 5 
wait they said the answer was in fraction
Unless my calculation went wrong somewhere 
Oo then calculations are probably right
I don't like such answers either
Why 29, give us 30
It would become a perfect 5
so then it's 5?
soo in first theorem, we had 2 points on each side, A,B and C,D
in this theorem we have a side with only 1 point 
but looking at first theorem
we multiplied the distance when we first touched circle, and distance when we touched it 2nd time
so with only 1 point, we touch only once 
why would we touch that
We can't touch the line?
there's a T?
yee in 2nd Theorem
check the 2nd theorem once
its totally different yet totally same
Oo you understood how 1st works right ?
we are finding 2nd theorem
in first we had 2 points on both sides so we did PA x PB = PC x PD
but this time we only have 1 point in bottom side
yes sir
in this case
what we do is PA x PB = PT x PT
multiply it with itself, it touched, and then it untouched
oh
Yesyes
look at 5th one
Yes sir
first we find y ๐
y
yes
why not x?
so how many times does that line touch the circle
because that uses the same theorem as last question
one time?
i dunno ยฏโ \โ (โ ยฐโ _โ oโ )โ /โ ยฏ
we multiply it with itself
oh okay okay ๐
nope
so 6?
from the point where they intersect
to the end
nope
X?
nope
oh my goodness
you tried each value written there lol
1st, A,B are on same line right ?
nope
oh
Yes sirr
so, on one line there is 4 and 14
so 14 was a close guess
but 14 is distance from A to B right ?
A being point where it first touched circle
but we don;t want A to B
we want P to B
so we can add distances from P to A then A to B
mkkayy
so what was distance from P to A
do i have to multiply something?
Yes please
4!
๐
yeahhh
so whats AB 
14?
๐
4x14?
why multiply
yes
why not
YAUUHH
PB = PA + AB right ?
oh ye
now we know PA and PB
Yes we do
Yesyes
whats PE
yup
Yes
so y^2 = 4 x 18
I thought it was plus?
hmmm mkay mkay
so y = $\sqrt{72}$ ?
Akki#gtfoanemia#ViataGod
you told me 
here
Yeah
Akki#gtfoanemia#ViataGod
there
okioki
4 x 18 = 72
Yes yes
so $y^2 = 72$
Akki#gtfoanemia#ViataGod
Akki#gtfoanemia#ViataGod
What happened to the 2?
that was square 
Yeah
so it became square root
Akki#gtfoanemia#ViataGod
6?
how 
cause I see it
look from P to C
C is the point from where arrow is fron
6?
nope, thats CD
oh
what would PD be ๐
is it x + 6?

I'm right?
yes
yassss ๐ฅณ
now, PC x PD = PA x PB right
yessir
oh no
4+14?
that was PA x PB ?
was it?
this is just PB
yes
whats 4 x 18 ?
72?
Akki#gtfoanemia#ViataGod
eh
$x^2 + -6x + 12x -72 = 0$
Akki#gtfoanemia#ViataGod
this is right, right ?
i don't know..
whats 12 - 6 
6?
whats 12x - 6x
6x?
yes
oh oki
so I wrote 6x as 12x - 6x
now lets write it like this $x(x-6) + 12(x-6)$
Akki#gtfoanemia#ViataGod
$(x+12)(x-6) = 0$
Akki#gtfoanemia#ViataGod
kkk
what are the 2 values when this will be 6 ๐
x?
yes
either x+12 should be 0 or x-6 should be 0 right
yes sirrr
at what x does x+12 = 0
if x = 6 then x+12 = 0 ?
yeah?
Will it tho?
-12+12 = 0
oh
thats 1 solution, but it can't work
as we can't have negative distance
so there has to be another solution
which we get from here
either (x+12) is 0 or (x-6) right
lets see when x-6=0
so at what x is x-6 , 0
how do I do that tho
then what
nothing 
wait what
that was the x in the circle thingy?
i'm guessing it is
oh my then thank you very much you're very helpful sir
thank you thank you ๐
its this x
ooo you mean angle
it wasn't angle