#determinant fast method
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Well there is a fast method to solve this take the same matrice as presented but with only 0 instead of x and with opposite coefficients ( let’s call it A)
Here the matrice presented is x*I3 -A
And for x in C the determinant of x*I3-A is 0 if and only if x is an eigenvalue of A
here 5 is actually an eigenvalue
Because if you replace x by 5 the matricés rank is 2 thus it’s determinant is 0
Then knowing that 5 is an eigenvalue and that the determinant is 0 you can directly calculate the determinant with respect to x by substracting the last column to the first one and then calculating the determinant by developing using cofactors
Then factor by (x-5)
You’ll have a quadratic to solve
I didn't understand the starting line
Forget it I just realized it’s not really important
But look at the matrice for x=5