forgot how to do this help

[leaden lance]

.

[chrome violet]

1. Wait patiently for a helper to come along.
2. Once someone helps you, say thank you and close the thread with:

+close

3. Feel free to nominate the person for helper of the week in #helper-nominations
4. Do not ping the mods, unless someone is breaking the rules.
5. If you're happy with the help you got here, and the server overall, you can contribute financially as well:

[stiff mountain]

which question do you need help with?

[leaden lance]

the last one

[stiff mountain]

you drew the graph wrong tho

it doesn't pass through (0,0)

[leaden lance]

k fixed

now tell last

[stiff mountain]

$3x^2-4x-2=(3x^2-2x-1)-(2x+1)$

[celest wren]

scilent

[stiff mountain]

so $3x^2-2x-1=2x+1$

[celest wren]

scilent

[stiff mountain]

the line you need to draw is that

and the point where the 2 graphs intersect is the solution

[leaden lance]

nro wtf is this

💀

[leaden lance]

how did u even get this

[stiff mountain]

isn't that what the last question asked for?

[leaden lance]

and what does the -1 < x < 15

thing mean

[stiff mountain]

it means you have to only look at x between -1 and 1.5

you don't care about any other x

[leaden lance]

ohh

[leaden lance]

?

[stiff mountain]

I subtracted 3x^2-2x-1 from 3x^2-4x-2

to get the equation of line

[tropic star]

When there's a horizontal tangente, try to curve the curve in that point as if it were a part of a circle

[leaden lance]

and the equation is 2x +1?

[stiff mountain]

yes

[leaden lance]

but isnt this supposed to be 2x-1

[stiff mountain]

no it gives -2x-1

[leaden lance]

which is same as 2x+1?

[stiff mountain]

no

[leaden lance]

then how did u get 2x+1

[stiff mountain]

3x^2-2x-1 -2x-1=0
so 3x^2-2x-1=2x+1

if you want to find the points where 2 curves intersect, solve them

here the 2 curves are

y=3x^2-2x-1 and y=2x+1

[leaden lance]

where did u get the -2x-1

[leaden lance]

i mean how does this give

-2x-1

bro what curve

[stiff mountain]

by subtraction

[leaden lance]

oh ye

kk got it

so after -2x-1

[stiff mountain]

3x^2-4x-2-(3x^2-2x-1)=(3-3)x^2+(-4+2)x-2-1=-2x-1

[leaden lance]

this

[stiff mountain]

these are the 2 curves

where they intersect y value must be the same

so 3x^2-2x-1=2x+1

3x^2-4x-2=0

[leaden lance]

so after this what to do

[stiff mountain]

which is the equation whose roots we have to finde

[stiff mountain]

draw the line

y=2x+1

[leaden lance]

ok

[stiff mountain]

x coordinates of points where the line and the parabola intersect is the solution to the quadratic equation

[leaden lance]

idk how

💀

[stiff mountain]

you know how we solve linear equations in 2 variables graphically?

[leaden lance]

solved

got help from brother