#Finding the values of 2 variables in 2 equations w/ 1 constant each

35 messages · Page 1 of 1 (latest)

frank geyser
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Sorry for the long title. Is it possible to solve for both x and y given what is known from both of these 2 equations? If so, how is it done?

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wet grove
frank geyser
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Thank you for the timely response. Sorry, I'm not familiar with how to do substitution in this case. Could you elaborate on how to do that with two equations and variables?

wet grove
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how can you make $\frac xy=1.53$ not have a fraction bar

amber ravineBOT
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!𒐪 ɹɐupoɯ⇂ㄥ8𝟝 𒐪!

wet grove
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wait btw what is 1.53…. exactly

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is it some fraction

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if so convert it to said fraction

frank geyser
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yes... 153 and 11/13

wet grove
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11/13 is not 1.53

frank geyser
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153 and 11/13ths

wet grove
wet grove
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where did you get 1.53…. from

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like what’s the context to this

frank geyser
# wet grove like what’s the context to this

Sorry, I was absolutely looking at the wrong thing. 1.53846 is the exact constant in the first equation.

The context is that the first is supposed to be a ratio of hours, and I'm supposed to find the number of hours represented by X and Y given that ratio of 1.53846.

wet grove
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it’s exactly that or was it from a fraction

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a fraction makes this neater

frank geyser
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Let me see if I can copy the exact problem. 1 moment. Thanks for your help and patience.

frank geyser
# wet grove a fraction makes this neater

It's definitely possible I'm asking the wrong question here. I know the ratio is 1.5384615384... from the fraction 80/52. Forgetting for the first equation for the moment, which would obviously just be 80/52, with that ratio of 1.53... or the fraction 80/52 (not representing the first side of the first equation)... how does one solve for X and Y in the second equation?

Sorry If I'm adding to the confusion here.

wet grove
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80/52 is nice

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so normally you solve systems by

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isolating one variable in terms of the other

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and then substitution right

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how do you do that here

frank geyser
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It's close, but because I'm converting a fraction to decimals, it's not exact.

wet grove
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dont use decimals just keep it in fraction form

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but yea thats how you do it!

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isolate the x and substitute

frank geyser
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Thank you!

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+close