Gradient of tangent to curve at y=-1 | Mathematics | Page 1

iron junco Dec 29, 2023, 8:33 PM

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river remnantBOT Dec 29, 2023, 8:33 PM

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iron junco

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iron junco Dec 29, 2023, 8:45 PM

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Also show that the curve has no stationary point

solar dust Dec 29, 2023, 9:02 PM

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iron junco

Hm... Let's try reversing the roles of x and y:
dx/dy = (3y^2 - 2x + 4)/(2y)
After we simplify a bit:
ydx/dy + x = (3/2)y^2 + 2
This is a linear DE for x(y).

iron junco Dec 30, 2023, 12:33 AM

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Wym reverse roles

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How does that work

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Also what does DE stand for

inland shuttle Dec 30, 2023, 3:50 AM

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iron junco Wym reverse roles

Taking reciprocal

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De stands for differential eq

void spindle Dec 30, 2023, 4:09 AM

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why're you guys solving the de?

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oh wait you have to 💀

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@iron junco do you know how to solve linear differential equation?

solar dust Dec 30, 2023, 7:35 AM

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Not sure what you're doing here, but that's not correct.

whole needle Dec 30, 2023, 7:40 AM

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void spindle oh wait you have to 💀

i don't see why, solving it brings you no closer to a particular gradient
you need an x value still

solar dust Dec 30, 2023, 7:45 AM

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Yes, by the way. The x-coordinate is still kinda necessary.

iron junco Dec 30, 2023, 1:47 PM

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void spindle <@785610065218240573> do you know how to solve linear differential equation?

No

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Btw I got the gradient I just need to show that it has no stationary point now

#Gradient of tangent to curve at y=-1