how did they get a 2

[forest crescent]

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[low jetty]

casssualy following : Wait patiently for a helper to come along.

casssualy following : Wait patiently for a helper to come along.

casssualy following : Wait patiently for a helper to come along.

[tulip copper]

you mean the 2 for k?

[low jetty]

Ye

[tulip copper]

it should not be 2

k should be 5

vertex of a parabola (h,k)

[low jetty]

Oh wait

I’m so dumb

[tulip copper]

nah your not

[low jetty]

Okay so how do I uhm find the x intercept

Because by counting down the squares it doesn’t work

[tulip copper]

do you have the equation for the parabola?

[low jetty]

It’s gonna be uhm

[tulip copper]

go ahead

[low jetty]

(X+ 9/2)^2 + 18

,, (X+ 9/2)^2 + 18

[crimson pond]

Expired

[low jetty]

I think

[tulip copper]

this opens upwards

[low jetty]

Oh uhm

[tulip copper]

just send me the picture

of the full question

[low jetty]

Uhm forgot the negative

[tulip copper]

to find x intercept just put the y = 0

[low jetty]

Ohhh so it’s like ,, 0 = -x^2 -9x -18

[tulip copper]

and solve it

yup

[low jetty]

,, 18 = x^2 - 9x

[crimson pond]

Expired

[low jetty]

And uhm

Uhm

[tulip copper]

use the quadratic formula

[low jetty]

-B sqrt -b2 -4ac/ 2a right?

,, -B sqrt -b2 -4ac/ 2a right?

[crimson pond]

Expired

[low jetty]

Shoot

[tulip copper]

,, -b \sqrt b^2 -4ac/ 2a

[low jetty]

Isn’t it -b^2

[tulip copper]

,, -b \sqrt( b^2 -4ac)/ 2a

[tulip copper]

b^2

+/-

outside

[low jetty]

How do I know when to add and when to subtract

[tulip copper]

u do both of them

[low jetty]

Ohh cuz it’s a parabola and 2 x intercepts okay got it

[tulip copper]

also y = -18 not 18

[low jetty]

Where

[tulip copper]

y intercept

[low jetty]

fixed.

[tulip copper]

you can find it by putting x = 0 and checking

[low jetty]

Also for this inside square root we will do -9^2 right

[crimson pond]

Laplace

[tulip copper]

in you case a =-1 b= -9 and c= -18

[tulip copper]

yes , (-9)^2

[low jetty]

I’m doing it like this

[tulip copper]

$$x = \frac {9 \pm \sqrt{(-9)^2 -4(-1)(-18)}} {-2},$$

[low jetty]

Wait I have -9 - √9

[crimson pond]

Laplace

[low jetty]

I have -9 - √9

and we can’t have negative square roots I believe

[tulip copper]

,, you cant have \sqrt {-1} as its complex

[crimson pond]

Laplace

[low jetty]

Oh so the negative as too be inside the square root for it to not be solvable?

[tulip copper]

you can still solve it but its in comlex plane

and yes if -ve is inside its complex

[tulip copper]

$$x = \frac {9 \pm \sqrt{81 -72}} {-2}$$

[crimson pond]

Laplace

[low jetty]

Oh wait

I forgot the divisions

[tulip copper]

mhm its divided by 2a

[low jetty]

So makes me get the x intercept in fractions

Matter of fact in square roots

I’m stuck at √9 over -2

[tulip copper]

what is sqrt9 ?

[tulip copper]

also in rang it should 9/4 not -9/2

[low jetty]

Ignore the x1,x2

[tulip copper]

,,\sqrt 9 = 3

[crimson pond]

Laplace

[low jetty]

It is still divided by -2

Under it

can we do the adding one together?

[tulip copper]

,, \frac {9+3}{-2}

[crimson pond]

Laplace

[low jetty]

What the

So in the square root we have √9 / -2

[tulip copper]

wait hold on

[low jetty]

So basscialy we are trying to factor out -9/2

[tulip copper]

listen

[low jetty]

Mhm

[tulip copper]

$$x = \frac {9 \pm \sqrt{9}} {-2}$$

[crimson pond]

Laplace

[tulip copper]

you have this

,, and you know that \sqrt9 = 3

[low jetty]

The division is all over the equation?

[tulip copper]

yes

[low jetty]

Ohhhh

That’s what I was missing

[tulip copper]

$$x = \frac {-b \pm \sqrt{(b)^2 -4(a)(c)}} {2a},$$

[crimson pond]

Laplace

[tulip copper]

this is the equation

[low jetty]

Yea I’m at the part of 9+ 3 /2 = 12/2 = x1 = 6

OOO LA LA

[tulip copper]

-ve

the 2 has a -ve sign so 6 should also have it as we just have 1 -ve

[low jetty]

So x1 = -6

Right?

[tulip copper]

yup

now x2

[low jetty]

So uhm we are at -9 -3 / 2 = -12/-2 = x = 6?

I’m-

Why did I have positive 9 in x1 and negative in x2

[tulip copper]

$$x2 = \frac {9 - 3} {-2}$$

[crimson pond]

Laplace

[low jetty]

Why is it uhm positive 9

Isn’t the formula -b

[tulip copper]

it has -b here and b you have is -9 so -(-9) = 9

[low jetty]

Ohh

Okay

So x2 = 3

Or no wait -3

No it’s +3

Ye +3

Wait no

-3

[tulip copper]

yup

[low jetty]

Thx so much @tulip copper

[minor ivy]

@low jetty has given 1 rep to @bronze peak

[tulip copper]

yw also fix the range

[low jetty]

I added a negative that was it I beleive also u we’re saying something about the max

Of no

That was y-int

[tulip copper]

@low jetty

[low jetty]

So my whole parabola is wrong?

Or no

Wait what does range tell us about the parabola

Is range the Vertex’s Y?

[tulip copper]

the set of possible output value

thats range

[low jetty]

Can I get uhm a simpler definition

[tulip copper]

9/4 being the max you cant have anything above it but you can have all the values below it

[tulip copper]

its basically think of it as a vending machine all the things inside you can get is your range

[low jetty]

Oh wait I think I remember kinda you use the table of values

U write x and y on the sides

If there is an X value u like put that value where u see x

And u get the y

Something like that domain range stuff

[tulip copper]

yup

Anything else you need help with?

[low jetty]

Nope that’s it for today

I beleive

Thanks for coming and helping me

Have a good day/night

[tulip copper]

u too

[tulip copper]

np and gl with your studies

you can close this thread since we are done

[brave bane]

The tickets system is disabled for this server. Enable it at: https://yagpdb.xyz/manage/624314920158232616/tickets/settings.

[low jetty]

+close