what's the problem?
#Part 2:
willow fern
glad kindle
also, n can't be -1
that's possible. see #1183754217404514364 message for the approach
i mean the reciprocal function's definite integral can be proved using Riemann sums ofc RHS is log, not polynomial
https://math.stackexchange.com/a/4471487/290189
in fact, part 1 is enough for the desired result. as long as there's an expression
|riemann sum - a constant| < error in terms of n or h,
where n is the number of partitions or h the width of each equally divided subdivision, then it's fine.
