#Affine combination problem
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i just solved this equation for c1v2 + c2v2 + c3v3 = y
and in the end i am getting y = y after finding my constants
but im not getting c1 + c2 + c3 = 1
so its not fulfilling the condition for affine combination
c1v1 + .. you mean
This approach is correct. We solve
c1v1+c2v2+c3v3 = y
c1+c2+c3 = 1
im not getting c1 + c2 +c3 = 1
but im getting y = y
so that means y cannot be written as an affine combination of v1 v2 v3?
$$ \begin{cases} c_1v_1+c_2v_2+c_3v_3 = y \ c_1+c_2+c_3 = 1 \end{cases} $$
aL
this is the system you solve
so i solve both of these together? or i solve c1v1+c2v2+c3v3 = y this first to get the values of my constants
no you don't solve one of them first, they are a part of the same system
you have to solve the system
can you please explaint a bit on how to solve this system?
$$ \begin{cases}-3c_1 + 0c_2 + 4c_3 = 17 \ c_1 + 4c_2 -2c_3 = 1 \ c_1 -2c_2 + 6c_3 = 5 \ c_1+c_2+c_3 = 1 \end{cases} $$
aL
3 parameters, 4 conditions