#someone can help me
84 messages · Page 1 of 1 (latest)
2a+20 + 220 + x = 360?
!𒐪 ɹɐupoɯ⇂ㄥ8𝟝 𒐪!
@astral fog


if its $2\theta$ then youre very close to the correct track
!𒐪 ɹɐupoɯ⇂ㄥ8𝟝 𒐪!
however you have three variables and you need to find more possible equationsn
Is it
I understand
wait
quadrilateral with fact 80 grades:
80+220+2a+ 2$\theta$ =360
fene
nope
you have three varaibles here
meaning you need three equations to solve for each
but this is correct?
The another equation is x+a+theta= 360
like this one?
yep
are the angles 2a or just a
a
this is also wrong, check again
I didnt check it
For this, the equation is a+0+220+80=360?
yup
yup
wait no
red is wrong
youre missing an angle there
everything else is good tho
+280*
yes i know
x+a+0+280= 2a+ 2theta+ x+220
If both are worth 360, I can match them, can't I?
yup
x=20?
Match the two quadrilaterals, the green with the red and end in an "x+280=300".
i would recommend plugging in all the values for the systems youve found
like for a and theta
and then check if everything does sum to 360
ok
I have not been taught that yet, could you explain it to me please? I think I confused it with another topic
oh so like
solve the simultaneous equations for all values
then check if they actually work
its a very basic double check method i usually do to make sure
Like this? x+a+theta+280=a+theta+220+80
what I did was to simplify theta and a
x+280=220+80
nono like
once you have the numerical values of a, theta, and x
plug them in
like replace the diagram with all the values
and see if it makes sense
how
For red and green quadrilateral
Is it
300+theta+a=300+theta+a
But how to get that?
solving simultaenous equations
