Need help with a question | Mathematics | Page 1

weary badgeBOT Nov 16, 2023, 4:49 AM

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kindred bough Nov 16, 2023, 5:49 AM

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systems of equations/simultaneous equations

gleaming nimbus Nov 16, 2023, 5:55 AM

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could you please explain further, i have not much experience with algebra

kindred bough Nov 16, 2023, 5:57 AM

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do any of the two terms there seem familiar to you

gleaming nimbus Nov 16, 2023, 5:57 AM

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simultaneous equations

kindred bough Nov 16, 2023, 5:58 AM

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nice

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so how can you use those here

gleaming nimbus Nov 16, 2023, 6:02 AM

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wait 1 sec

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i think i might have figured it out but could you resolve the problem so i can verify my answer

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i wont ask for your answer before i give mine and i wont ask for your answer if im wrong

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i just want to see if im correct

kindred bough Nov 16, 2023, 6:03 AM

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just show your steps

gleaming nimbus Nov 16, 2023, 6:04 AM

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c after number = curved s after number = straight

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4c + 7s = time to paint ACCOUNTANT

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2x + 5s = 25
4c + 3s = 29
for solve 3 equations

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4c + 3s - (4c + 10s) = 29 - 50

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-7s = -21

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solving for s = 3

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sub back into equation 1 to find c

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2c + 5(3) = 25

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2c + 15 = 25

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2c + 10

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c = 5

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so s=3 and c=5

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?

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then solve for accountant

kindred bough Nov 16, 2023, 6:07 AM

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i would recommend checking by simply

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plugging both into both equations

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and seeing if it satisfies

kindred bough Nov 16, 2023, 6:07 AM

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gleaming nimbus then solve for accountant

yup then just do that

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you got it! great job

gleaming nimbus Nov 16, 2023, 6:08 AM

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so is that correct? or should i also check

kindred bough Nov 16, 2023, 6:13 AM

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you should check its a good habit

gleaming nimbus Nov 16, 2023, 6:14 AM

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ok ok

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could you tell me if i check correctly

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to solve for c and s eliminate one variable, multiply equation 1 by 2 and subtract it from equation 2

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(4c +3s) - 2(2c + 5s) = 29 - 2(25)

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4c + 3s - 4c - 10s = 29 - 50

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-7s = -21

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divide both sides by -7 = s = 3

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now sub s into equation 1

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2c + 5(3) = 25

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2c + 15 = 25

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2c = 10

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c = 5

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then 4c + 7s = 4(5) + 7(3) = 20 + 21 = 41

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does that look about right

kindred bough Nov 16, 2023, 6:21 AM

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gleaming nimbus could you tell me if i check correctly

so like we know c,s is 5,3
so
2(5) + 5(3) = 25
10 + 15 = 25
this is true

4(5) + 3(3) = 29
20 + 9 = 29
this is true

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just do that

gleaming nimbus Nov 16, 2023, 6:40 AM

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kindred bough so like we know c,s is 5,3 so 2(5) + 5(3) = 25 10 + 15 = 25 this is true 4(5) +...

but thats what im checking for

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to see if c,s is actually 5,3

kindred bough Nov 16, 2023, 6:47 AM

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you can do that by substituting it in

gleaming nimbus Nov 16, 2023, 6:52 AM

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i substituted the value of s into equation 1 to find value of c

gleaming nimbus Nov 16, 2023, 6:52 AM

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gleaming nimbus now sub s into equation 1

here

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im not sure if i correctly understand what you are trying to say so sorry if im being a bit annoying

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