help can someone solve this if

[serene otter]

if x was (the value in the pic)
find dy/dx
when x=2
dy/dx !!! NOT DX/DY

[cedar timber]

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[serene otter]

why is x= and not y=

this is how the question

it's high a abilities question

[serene otter]

this is the way i solved it

i don't think it's right tho

[serene otter]

?

[serene otter]

this question is for students who are smart
sorry for bad english

.

ok

$x = \sqrt{y^2+3y}$

[nimble owl]

Xenon

[serene otter]

$\text{find the value of } \frac{dy}{dx} \text{ at } x=2$

[nimble owl]

Xenon

[serene otter]

ok so, you rearrange for y

$x^2 = y^2+3y$

[nimble owl]

Xenon

[serene otter]

$y^2+3y-x^2=0$

[nimble owl]

Xenon

[serene otter]

$(y+\frac{3}{2})^2-(\frac{3}{2})^2-x^2=0$

[nimble owl]

Xenon

[serene otter]

$(y+\frac{3}{2})^2=x^2+\frac{9}{4}$

[nimble owl]

Xenon

[serene otter]

$y=-\frac{3}{2}\pm \sqrt{x^2+\frac{9}{4}}$

[nimble owl]

Xenon

[serene otter]

now take the derivative

where should i use x=2

at the very end

oh

you will get dy/dx = f(x)

then put 2 into x

what about the way i solved it

is it right

[opaque orbit]

Bro ?

No

[serene otter]

what

@serene otter tysm for your help

[native dock]

@split plank has given 1 rep to @lilac garden

[serene otter]

:) ofc

[serene otter]

close

+close