#Probability distribution of winning ticket
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vin100
so u shld b finding $P(X = x \mid N = n)$ first
vin100
,,X \sim \mathrm{Unif}({1, \dots, N})
vin100
so $P(X = x \mid N = n) = \frac1n$
vin100
for all $x \in {1, \dots, n}$
vin100
,,E[X \mid N = n] = \sum_{x = 1}^n x \cdot \frac1n = \frac{n+1}{2}
vin100