rain pecan
why are the limits of y taken as x^2<= y <= x and not x<= y <=x^2. I mean what i am thinking is x^2 has to be greater than x so shouldm't it be the upper limit ? I might be wrong but i still need an answer that would teach me the mechanism and logic behind it
tame kettleBOT
why are the limits of y taken as x^2<= y <= x and not x<= y <=x^2. I mean what i...
+close
anyone with any answers yet ?
signal sail
I am assuming top most function has to go on top and most bottom on the bottom?
rain pecan
how to identify top most funciton ?
signal sail
Look at ur graph
lean dust
$x^2$ is less than x for x in (0,1). Eg - $(1/2)^2 = 1/4 < 1/2$.
worn larkBOT
mark4slr
rain pecan
$x^2$ is less than x for x in (0,1). Eg - $(1/2)^2 = 1/4 < 1/2$.
okay yes that is understandable. But what if the value of x is (2)? then $x^2$ would be greater then $x$ . what about then ?
worn larkBOT
_Lunatically_
bleak bloom
okay yes that is understandable. But what if the value of x is (2)? then $x^2$ w...
Calculate the intersection points of the curves, then figure out which curve goes on top/bottom in that interval
otherwise you could just do rough sketch to figure that out as well
rain pecan
Calculate the intersection points of the curves, then figure out which curve goe...
would you give an example , that would make it more easy...if possible.
bleak bloom
just take this example:
Solve this equation to get the intersection points between fx and gx:
x^2 = x
solving this gives you the solution.
x = 0 and x = 1
in the interval (0,1) x is always greater than x^2.
therefore that curve will lie on top
sorry idk how to write latex
therefore the integration can be written has int 0 to 1 int x^2 to x dy dx
because dy goes from x^2 at the bottom to x at the top, while dx goes from 0 to 1