#huh
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you would do something like 3/76 is the probability of getting one red ball right?
Hello, could anyone help me with this?
let the number of red balls be x
so lets just say i had a bag of 5 marbles and 3 of them are red whats the odds that i draw 2 red from 2 random draws
not quite
the second ball has a lower chance of being red than the first, given you just took one of the red balls out
oh true
so do this
what's the chance that the first one you pull out is red, then
3/38-3/76?
just do it in terms of x
x red balls out of 20 balls
okay so lets break down the example for 3 red out of 5 red
the number of possibilites for our first draw is 5 possible balls then we have 4 possible balls
then for the cases we want
we first want to pull out any of the 3 red balls then any of the 2 red balls
so we get 3x2 / 5x4
makes sense?
yes
so there are x red balls in 20 total balls
what's the chance that just the first one you pull out is red
yes that's right
ok good
and how many red balls are left
yes
so what's the chance the second one would be red also
and since you are looking for 2 events both to be true, you multiply the probabilities
that's just standard probability things
like for example
flip 2 coins, what's the chance they're both tails?
1/2 for the first, 1/2 for the second
oh i see
you want to multiply them to get 1/4, since they're independent and you want them both to be true
got it
anyway, yes
omg this makes so much sense now
I ligit love you i need that i have an exam tomorrow haha
no like thats actually
like
omg
i get it

:D nice