#Finding the equation of the normal to a line

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lusty sage
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lusty sage
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can't lie

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this makes absolutely no sense

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the exam board are waffling with this one

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I can get the gradient as being -1/4π+1

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and the point of intersection as (π, 2π^2-sinπ)

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which is just (π, 2π^2)

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+close