#Proof of cos(𝘢) sin(𝘢 + 𝘣) = sin(𝘣) + cos(𝘢 + 𝘣) sin(𝘢)
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since theyre using chatgpt they dont have a brain and cant actually think
does this whole thing expand to be equivalent to just cos(a)(the expansion of sin(a+b))? there are geometric proofs for those
stop using chat gpt. if you know the content help if not get out
I don't think so, but are there any geometric proofs for cos(a) sin(a + b) = sin(b) + cos(a + b) sin(a)?
But I'd also be okay with a geometric proof of cos(a) sin(a − b) = −sin(b) + cos(a − b) sin(a).
Perhaps something involving two triangles?
@paper warren, is this what you mean?
cos(a) sin(a + b) = sin(b) + cos(a + b) sin(a)
cos(a) (sin(a) cos(b) + cos(a) sin(b)) = sin(b) + cos(a + b) sin(a)
cos(a) sin(a) cos(b) + cos²(a) sin(b) = sin(b) + cos(a + b) sin(a)
cos(a) sin(a) cos(b) + cos²(a) sin(b) = sin(b) + (cos(a) cos(b) – sin(a) sin(b)) sin(a)
cos(a) sin(a) cos(b) + cos²(a) sin(b) = sin(b) + sin(a) cos(a) cos(b) – sin²(a) sin(b)
cos²(a) sin(b) = sin(b) – sin²(a) sin(b)
cos²(a) sin(b) + sin²(a) sin(b) = sin(b)
sin(b) (cos²(a) + sin²(a)) = sin(b)
cos²(a) + sin²(a) = 1, sin(b) ≠ 0
Where did you find this?
Wikipedia
Let f:a ↦ LHS-RHS. We have f(0)=0 and f’(a)=0
That's assuming they know calculus
They want all the proofs, it is one of them. Another proof maybe outside their knowledge would use complex numbers. If trigonometric identities were allowed, it would be shorter to expand sin(b+a-a). And then my proof would allow to prove the trigonometric identities like sin(a+b), but only to check them, not to find them in a constructive manner, except for finding one from another
YAP with power series
Can you send me the link pweez?