Show that the sum of the cubes of the first n positive numbers is n^2(2n^2 -1)
#Series question on cubics.
light bison
azure jewelBOT
Show that the sum of the cubes of the first n positive numbers is n^2(2n^2 -1)
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deft sonnet
Show that the sum of the cubes of the first n positive numbers is n^2(2n^2 -1)
it's not
n=2 already fails there
deft sonnet
it's 2 times something lol
so yes it's even, that's besides the point
the question as you've stated is wrong
since, $1^3+2^3=9$ and $4(8-1)$ is 1) even and 2) not 9
tropic terraceBOT
Omegabet_
deft sonnet
Post the questio verbatim.
pearl verge
The sum is (n(n+1)/2)^2. Use induction.
For culture
https://archimedes-lab.org/2020/02/15/visual-proof-sum-of-cubes/