#Proving an inequality

62 messages · Page 1 of 1 (latest)

steady root
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Hi! I need help with this inequality.
I have to prove that for any real numbers $a,b,c$ such that $a^2 + b^2 + c^2 =1$ the following inequality holds
$$2\sqrt{2} \leq |a+b+c| + |a+b-c| + |a+c-b| + |b+c-a|$$

latent pierBOT
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snaky_man

velvet leafBOT
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oblique echo
steady root
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Yes, I am aware, the problem is, I haven't found a good way to do it

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$|x| = \sqrt{x^2}$, then you can use the condition in terms like $(a+b+c)^2$, but it didn't get me anywhere

latent pierBOT
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snaky_man

steady root
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$a^2 + b^2 + c^2 = 1 \Rightarrow a^2,b^2,c^2 \in [0,1]$ this means that $a,b,c \in [-1,1]$ which allows some trigonometric substitution but this also doesn't seem to great

latent pierBOT
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snaky_man

oblique echo
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Okay, feels like you're barking up the wrong tree with all this.

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I'm gonna tell you what I see.

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What's |a + b + c|^2?

steady root
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(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca)

oblique echo
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There's your 1.

steady root
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I know

oblique echo
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Why do you have the square root?

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Also, note |x| >= x generally.

steady root
latent pierBOT
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snaky_man

oblique echo
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Also, that's not exactly why you have it.

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At least, that's not the answer I was looking for.

steady root
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wait, do you want me to explain why is there even a square root in the first place?

oblique echo
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...I think so? I'm not quite sure what you mean, but do that and we'll see.

steady root
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wait

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I think I still don't understand what you're asking for

oblique echo
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Okay, look.

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sqrt((a + b + c)^2) = |a + b + c|, right?

steady root
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yes

oblique echo
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What else is equal to |a + b + c| that has (a + b + c)^2 in it?

steady root
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$\frac{(a+b+c)^2}{|a+b+c|}$

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?

oblique echo
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Right.

latent pierBOT
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snaky_man

oblique echo
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That's correct.

steady root
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hmm

steady root
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now it looks kind of like some form of cauchy-schwarz inequality

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other than that I don't see how this helps

oblique echo
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You know things like "Cauchy-Schwarz inequality" but you don't see how this helps?

steady root
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yes?

steady root
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is it really easy or what?

oblique echo
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I mean, I just don't see how you can dismiss it out of hand. Like, it's not a magic bullet, but it's a start of a chain of logic.

steady root
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okay, I will think about it

steady root
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I still have no clue on how to proceed, can you give me a hint?

steady root
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bruh got left on read

oblique echo
steady root
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To be honest, I don't know, I give up

steady root
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Sad

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Don't give up soldier

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The fight starts once you feel like giving up

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@steady root

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...

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I spent so much time on it and got nothing

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I'm tired

steady root
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got it

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thanks

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not with your approach though

scarlet kernelBOT
steady root
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+close