#Feynman's Integration Technique
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AstroVortex
Please help me!
Let $I(t) = \int_0^{∞} \frac{\sin tx}{x} dx$
(xy)²=(yz)²=(xz)²=xyyzxz=-1
from Leibniz rule
$I'(t) = \dv{t} \int_0^{∞} \frac{\sin tx}{x} dx = \int_0^{∞} \pdv {t} \frac{\sin tx}{x} dx$
Liebniz rule is the same as Feynman's technique
(xy)²=(yz)²=(xz)²=xyyzxz=-1
$= \int_0^{∞} \frac{x\sin tx}{x} dx$ (view x as a constant)
(xy)²=(yz)²=(xz)²=xyyzxz=-1
Well I have never heard of the Leibniz rule before
This is I'(t)??
So this shall become $$\int_{0}^{\infty}\frac{x\cos{tx}}{x}dx$$?
AstroVortex
from the chain rule
and over here shouldn't we think of t as a constant? Becuase we are integrating w.r.t x(you've written dx)
same thing as Feynman's technique
you should call it liebniz rule tho
yeah i meant that as the process of partial derivative
not the function itself
oh yes yes
so we integrate this?
wait im not entirely why why bprp use e^-tx
Multiply integrand by e⁻ᵃˣ then perform two integrations by parts
@pale kite in this?
or this?
the original integral
okay
the reason you don't put your variable inside the sine is because the integral of cos doesn't converge on one value
apex predator
hmmmmmmmm
apex predator
ahh ok
apex predator
differentiating that is a little less simple than e^-xt but it works I reckon
i see
nevermind it won't
skull
yeah this is bprp's way
apex predator
so it won't work
i see
apex predator
Will take me time to digest
the most difficult part to wrap your head around the first time is finding your C, in my opinion
I should add that the integral only works because t≥0
It will take some rigorous penance!
Instead of integrating by parts, one can also see -sin x as the imaginary part of e⁻ⁱˣ
i sinx = sinh ix
i think you can
,w graph sinh(ix)
,w graph -i sinh(ix)
move i to the right side
skull emoji
Or maybe I'm a bit too dumb 😭
you aren't bro
Ok lemme look up for another eg.
you're good at your age
Thanks
@broken osprey has given 1 rep to @low dirge
Hey I can't find it
Do you know any other examples?
Ohhh
Found it
$\int_{0}^{\infty}e^{-x²}\cos{5x}dx$
AstroVortex
From bprp
And yes, I didn't understand what he said in the video
Can you help me @low dirge ?
i dont think i can
this topic is way beyond my knowledge rn
@visual tusk
sort of
apex predator
that term you can see goes to 0 on both 0 and infinity
apex predator
to find your C you can set your t to 0 and that leaves the Gaussian integral from 0 to infinity
@low dirge no integrate exp(-(i+t)x) and then take the imaginary part
idk how familiar they are with complex numbers so it may be easier to just do it the purely real way
Nah I am good with complex numbers but I am trying to learn this method
We had this
you integrate by parts and look for your original integral
as seen here
What time is it in your country rn?
7
My brain is getting fried
So can you explain me tomorrow? Pleaseee
Ig ill be able to grasp better when I wake up
possibly
you have your xe^-x²cos(tx) and you integrate by parts with xe^-x² as what you're integrating and cos(tx) as what you're differentiating
@visual tusk
apex predator
and that other part
you can see that's the integral you started with bar some t
so you can replace that with just I(t) and solve the differential equation
@visual tusk I'd really prefer to finish today
if possible
Ok lemme try
You know any tricks to freshen my mind in 5 mins?
Why doe we have a 2 in the denominator?
oh sorry you're doing IBP
ok so I(t) = $\frac{\sqrt{{\pi}}}{2}e^{\frac{-t^{2}}{4}}$
AstroVortex
ok so we have fount I(t)
now you look to what you started with and you see that t=5 for that integral
we have to solve dI/dt = -t/2 I
wdym?
apex predator
hm yea
which is a separable differential equation
hmmmmmm
apex predator
integrate both sides
If I put t = 5 here, I'll get $$\frac{\sqrt{\pi}}{4}e^\frac{25}{4}$$
AstroVortex
sorry typo
but yes that's your integral
broken latex
wh
apex predator
I hate when I make a mistake with placement of curly brackets
pain to read back through
yup
@broken osprey has given 1 rep to @worldly wolf
Ill read the chats again
ok
mb then itll be crystal clear
alright
and yeah thanks @low dirge your effort was admirable
@broken osprey has given 1 rep to @low dirge
apex predator
huh? noice!!!!!!!!
you may see it again? although it's very specific
apex predator
no, why?
what??
oh leave it
I'm curious now
I'll tell you some other day
yeah so I told chatgpt that at my place its mn
and your time
so I asked for the timezone
in whcih you live
but it was inaccurate lol
yeah I'm English, it's way off
USA?
good luck with your Feynman's trick