#proof for equation
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yes
so im supposing $V_E$ here means final (end) velocity and $V_S$ means initial (starting) velocity
wolfqz
Acceleration is given as the change in velocity per unit time. So,
$$a = \frac{\Delta v}{t} \implies t = \frac{\Delta v}{a}$$
$$\text{Average Velocity} = \frac{V_E+V_U}{2}$$
$$\text{Distance = Average Velocity} \times \text{Time}$$
$$s = \frac{V_E+V_U}{2} \times \frac{V_E-V_U}{a}$$
$$s = \frac{V_E^2 - V_U^2}{2a}$$
wolfqz
Bro it's a Physics Question ☠️💀
its just asking to prove the third equation of motion
That doesn't change the fact that it's a Physics question
Ok leave that it doesn't matter
Pardon me
AstroVortex
Thank you ❤️