#Summation Notation
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$a_n = a_0+(n-1)d$
xNiden
No Lifer #GTFOanemia
now you wish to find a partial sum ryt
yes
remember the formula to find the sum up till n terms of a geometric sequence
$a_n = 5(5)^{n-1}$
xNiden
,calc 5(5)^{1-1}+5(5)^{2-1}+5(5)^{3-1}+5(5)^{4-1}+5(5)^{5-1}+5(5)^{6-1}
The following error occured while calculating:
Error: Symbol or string expected as object key (char 7)
or do I make you derive it lol
yeah, you're deriving it
alr
let's start with a loose notation of a geometric series
$a + ar + ar^2 + \dots + ar^{n-1}$
No Lifer #GTFOanemia
No Lifer #GTFOanemia
now, there's an identity which states that
$(x-a)(a^{k-1}+xa^{k-2}+x^2a^{k-3}+\dots+x^{k-1}) = \frac{x^k - a^k}{x-a}$
No Lifer #GTFOanemia
$S_n = \frac{a_1(1-r^n)}{1-r}$
xNiden
$S_n = \frac{5(1-5^n)}{1-5}$
xNiden
oof
No
No Lifer #GTFOanemia
continue from here
no i mean numerator
this would just be $S_n = \frac{5(1-5^n)}{1-5}$
I multiplied both numerator and denominator by -1
yeah that's correct
xNiden
oh
then where did the -1 go?
doesn't that mean it would be $S_n = \frac{-5(-1+5^n)}{-1+5}$
-1 times the numerator and it goes into ( )
xNiden
$\frac{5(1-5^n)}{1-5} = \frac{5(5^n-1)}{5-1}$
No Lifer #GTFOanemia
yep
ok i get it now
alr
i was confused sorry about that
,calc 5^6
Result:
15625
thanks for the clarification
alr
now I think you can solve
you have 5^6 now
so then i just put in 1-6 for n?
so $\frac{5(5^6-1)}{5-1}$
xNiden
yes
,calc (5(5^6-1))/4
Result:
19530
ay this is the same as calculating all of the values itself right
ah i see
yeah but quicker
oof
$\frac{5(5^6-1)}{5-1}$
xNiden
ima do it manually
try deriving their summation formula
alr
alr then
$\frac{5(15624)}{4}$
around there
the identity I used can be proved by the binomial theorem
Right
xNiden
but that's taught after geometric series I think
Wait
first divide
$\frac{78125}{4}$
xNiden
bruh
I’ve had that one
no
binomial theorem
$19531$
xNiden
yeah...
wait where did i mess up
,calc (5/4) x 15624
The following error occured while calculating:
Error: Undefined symbol x
,calc (5/4) * 15624
Result:
19530
lol
how
why would you divid 5/4 before rather than dividing it all together?
anyways, it's a calculation error
divide by 4 first
because you'll work w/ smaller numbers that way
,calc 5 * 15624
Result:
78120
,calc 78120 / 4
Result:
19530
Doesn’t really matter so idk how you got the wrong answer
Let me see
78125
Idk where that came from
Alr
that idk
oof
xNiden
but
in my calculator I did 5*5^6
cause I forgot the -1 which would make up for the 15624
that's why i was off by 1
Right
Seems logical
I wouldn’t even have had to learn this
if it wasn’t for my own choice
Perhaps my education system is different
no but like geometric is multiplication right and you had something else I don’t know the English term for it but it was addition
$a_n$ = $a_1r^{n-1}$
xNiden
$-32768$ = $-2*4^{n-1}$
xNiden
,calc -32768/-2
Result:
16384
$16384 = 4^{n-1}$
xNiden
,calc (-2(1-4^4095))/-1
The following error occured while calculating:
Error: Symbol or string expected as object key (char 10)
,calc (-2(1-4^4095)/-1
The following error occured while calculating:
Error: Parenthesis ) expected (char 17)
,calc (-2(1-4^4095))/-1
Result:
-Infinity
,calc (-2(1-4^4095))/-1
Result:
-Infinity