#Can someone help me and explain how to do a few?
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$\logadd$
wolfqz
$\logsubtract$
wolfqz
bro has the macro ready
also $\log_d a^b = b\log_d a$ is used
wolfqz
š„
Okay, so how do I use the formulas for this?
$\log_{a^x} b^y = \frac{y}{x} \log_a b$ better
(xy)²=(yz)²=(xz)²=xyyzxz=-1
Could one of you help me with one of them and then I can try to do one myself?
(xy)²=(yz)²=(xz)²=xyyzxz=-1
explain the logic too smh
basically reducing
from
expo -> multiply
root -> divide
multiply -> plus
divide -> minus
wolfqz
How do you know which formula to use?
practice
well not really
if u have something like $\log_3 uv$ say, then u know just by looking that its like $\logadd$ so u apply that
wolfqz
Bro, Iām asking which formula to use for each problem because there are multiple formulas. Wdym practice??
well if you practice you will get used to the math and you will know which one to use
āMommy, how you divide a fraction?ā The mom doesnāt provide an answer and just says āpracticeā without explaining how to do it. Essentially, thatās what you just did to me.
I am
didnt that help
No, I just learned this concept today so I am very new and just a little confused on the topic.
do u know the properties of logarithms
Just think in what form the question is and apply that property
do u know the properties
No
Ah
let me explain it for u then
so logarithms are just reverse of exponentiation
u know what exponentiation is right? @hallow copper
No, never even heard that term before. Is my teacher smoking something?
$a^b$
wolfqz
Ya
wolfqz
So basically its used for finding exponents
if your given $a^m = b$ then $m = \log_a b$
wolfqz
@hallow copper do u understand
Yes
Let $p = \log_a x$ and $q = \log_a y$
wolfqz
try going through this
let me present the proof yo
@hallow copper we start with this, if $p = \log_a x$ then $a^p = x$ by definition of logarithm
wolfqz
similarly $y=a^q$
wolfqz
@hallow copper do u understand till here
You know what, I couldnāt be more lost honestly. This isnāt helping. Sorry. Thanks for trying to help but this is just no use.
u can take the logarithms course on khan academy ^^
Iām just really mad rn as you can tell by my facial expression bro. And yes, thatās actually me.
Itās just not helping. Sorry
š„
But thanks anyways
Try taking the course on khan academy maybe thatll help
im no professional teacher so they will teach better than me ofc
yea seeing as text explaining isnāt really working Iād recommend watching videos on it @hallow copper