#14,16,20,22,23
110 messages · Page 1 of 1 (latest)
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close
- Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
.
wow you have a lot of quadratic questions
ang progress in those 2hrs
for 14 consider a and b as the side lenghts
no
ok so 2a+2b=400
and ab=8000
yup
what do i do from there
well what does it look like
no clue
two variables...
okay
systems of equations?
whats that
idk what that is
neither
so like how would you solve x+y=2
x-y=0
y=-x+2
oh
okay i can make them a equation
now i have y=-x+200 for the perimeter
what do i do for the 2nd one
substitute
roots
okay
i got 34.16 and 234.16 but the answer sheet says its 55.28 and 144.72
,w -x^2+200x-8000=0
,w 20(5+sqrt(5))
how u do that
okay you have a calculation error somewhere
k
i got it can we do 16
how does something get 2 zeroes
b^2-4ac>0
so what is b here
-3+2k
there you go
substitute here
ok
4k^2-12k-7>0
for the zeros i got 7/2 and -1/2
alright, now for the > sign
what about it
well it tells you your range
how do i know whats 2 zeros and whats none
remember this
so this is b^2 4ac blah blah
but this needs to be ABOVE 0
so uh
how would you solve this
ok lemme try
idk
okay remember a quadratic has two sections
so the x values between the zeroes and the x values not between the zeroes are either pos or neg
but not the same
so just test a value of x
now 20
assume the middle is a y=0, now find three points that are on the parabola and get the equation ax^2+bx+c and solve for a b and c
maybe it means at y=8 the two points are 6m apart
how do i do 22?
well when you see “will x hit y” what do you think about
the intersection
+close
