#permutations
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Say you have just 1,2,3. How many numbers can you create
3!
I think for (b) there can be more than 1 value of N
I’m not sure I understand how to do it still this was on my test and I need to correct it I think part A is 5! But don’t understand part b
How many digits can a number possibly have (in base 10) if none of the digits are repeated?
...no. Think about it. What is the most digits a number in base 10 can have before a digit must be repeated to add a new one?
oh 10?
Yes.
9876543210
Right. Now, let's take our condition into account. What is the smallest number of digits a base 10 number can have without repetition where the digits sum to 39?
987654? so 6 digits
Right. And since every permutation of those digits is a new number, how many numbers is that?
..."multiplied them all"?
because theres 9 possible digits for the first place then 8 in the next since theres no repeats?
so its 6!
Yes.
So there are 6! 6-digit numbers that satisfy our condition.
Now let's add a digit, but let's do it smart.
Let's add the digit 0.
Now, bearing in mind 0 cannot be the lead digit, how many numbers does this give us?
well thers 6 digits the number can start with so would it be 6 x 6! since thew others can be in any order?
Now, adding and subtracting the same amount doesn't change the sum, right?
I was thinking of replacing 4 with 3 and 0 with 1.
yes so it would then be 7 x 7!
Oh, you are writing down how many numbers we get for each case, right? Because we're going to need to add them all together.
Show your work on that?
yes
because there are 7 options for the first number 9,8,7,6,5,3,1 and then the other 7 numbers including 0 can be aranged in any order
but 0 does not add to the total so why can we use 0
Because that would be an 8 digit number. We're still counting 7 digit numbers.
ok i understand so it would just be 7!
Now, give me a chance to get to a piece of paper, because I think you might have accidentally been right.
ok lol
Okay, I was wrong. So anyway, 7!. Now let's add 1, subtract 1 again.
What would be the digits?
9876410
What's the sum of those digits?
You were right that we subtract 1 from 5. But then we add 1 to 1.
so it would be 9876432
Right.
would that be all the 7 digit numbers we can do?
since if 6 was taken out and replaced with 5 then an extra digit would be added making the total to 8
98754321
Yes, actually, but not for that reason.
Because if we subtract 1 from 6 we get 5, and there's nowhere we can add the 1 back without getting a duplicate digit.
Remember. We're subtracting 1 from one digit and adding it to another digit. We aren't "adding it" as a digit.
So should I continue finding all the combinations and then do I add the final numbers or multiply them?
...we're counting, right?
So if I asked you to count all the balls in a jar, and you counted all the red balls and all the white balls, would you add or multiply the two numbers to get all the balls?
Add.
We were moving onto the 8 digits
Right. So we can chuck a 0 onto the end of the two 7-digit sets we have.
What does that give us?
I meant what sets of digits does that give us? You're right, though.
98764320 and 98765310
Right.
So the 531 one we can't do much with except turn it into the 432 one. What can we do with the 432 one?
Add a 1 and take away from the 6 to get 5
Which yields?
8x8!
...no. The set of digits.
987543210
Where did the 0 come from?
It was from the 8 digit
Already been over this.
What we subtract from a digit, we add to a different digit, not as a new digit.
How so?
You tell me.
Are there any repeated digits? Is the digit sum what we need it to be?
Yes it would work
How many numbers does this give us?
Now there are 3 8 digit numbers
...no. How many permutations of these eight digits?
8!
Right.
There is only 1 way for the 9 digits right?
Yeah. Any subtraction addition we do here results in duplication.
So if I add all the results together that should be the answer
Yeah.
You might've made a mistake. Show your work?
Yes one second I’ll take a picture
I did those calculations
Then added the results from each
i got a new answer i got 448560
with the working above
This is correct.
yay thank you for the help
No problem. I know combinatorics can be intimidating, but if you just boil it down to casework and keep your head straight I find that it's relatively intuitive.
I mean, it's basically just counting.