Derivative (Implicit)

[supple oyster]

I am only able to get to the point of
dy/dx = 1/tan(x + y) * sec(x + y)^2 * (1 + dy/dx)
Not sure how to reach the showing part

[pulsar frigate]

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[devout siren]

@supple oyster since you've reached $\frac{dy}{dx} = \frac{\sec^2(x+y)}{\tan(x+y)} \cdot \left(1+\frac{dy}{dx}\right)$ the only thing you need is to multiply by $e^y$ both sides to get $e^y \cdot \frac{dy}{dx} = e^y \cdot \frac{\sec^2(x+y)}{\tan(x+y)} \cdot \left(1+\frac{dy}{dx}\right)$. To prove this is the same formula they gave you then demostrate that $e^y \cdot \left(\frac{\sec^2(x+y)}{\tan(x+y)}\right) = \left(1 + e^{2y} \right)$

[winged jasper]

Ambilogy

[devout siren]

That will show that their formula is obtained from yours, which is obtained by implicit dif.

[supple oyster]

Thank you @devout siren

[sharp ibex]

@supple oyster has given 1 rep to @devout siren

[supple oyster]

+close