#help
13 messages · Page 1 of 1 (latest)
do the same operation to all 3
wait i dont think you can moev all the x to the middle
huuuh
solve it seperately
split it in two yea
first solve 2x+3>(7x+6)/4
then solve (7x+6)/4>=3x+2
here there is a way to do it without manually finding all roots
it just asks $\frac{1}{\alpha^2} + \frac{1}{\beta^2}$ but we can rewrite as,
$$\frac{\alpha^2 + \beta^2}{\alpha^2\beta^2}$$
wolfqz
try to rewrite the numerator by completing the square and use some formulas regarding zeroes of a quadratic
@outer adder