#algebra
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the general approach is to rationalise it first @snow tulip
that is, make the denominator rational by multiplying both the numerator and denominator by the conjugate of the denominator
yep
Why do we bring the 5
wdym?
yes
Why do we bring the 5 and the root 3
its because the denominator wont become rational with it alone
what you CAN do is multiply by $\sqrt{3}+\sqrt{2}$
wolfqz
but that too only in this case
It’s like you turn the - into a positive question
yess
So if it’s 5 square root 2 + 2 square root 3 we will write it as 5 square root 2 - 2 square root 3
when you multiply a binomial with its conjugate, u can use the a^2 - b^2 property
this is why we multiply by that
to square the numbers in order to eliminate the square roots
Is it possible for us to do this together
My first step would be simplifying the radicals
Then timing them
And then just dividing
Multiply
So this confuses me right
It breaks the 5 and the -2 to divide it by 25
Is there any other way to do it
The -10 square root 6
yes $-10\sqrt{6} = 5 \times -2\sqrt{6}$
It broke it as (5 x -2) square root 6
wolfqz
he just used the reverse distributive property
Yea but is there any other way to do this
Like
I sometimes forget this
I don’t even know what I’m doing at this point
So I did square root 2 x square root 3 = square root 9
Breuh
how did u get the - 150 in the denominator
umm
Uhm
$\left(5\sqrt{3}\right)^2 - \left(5\sqrt{2}\right)^2 = 25 \times 3 - 25 \times 2 = 25$
wolfqz
youre supposed to get 25 in the denominator
wolfqz
I’m good at monomial radicals but bionomials are confusing
What do I need to work on
Like practice
I’ve been trying to study this for the whole day
Theek hai bhai
try rationalising these
isnt it supposed to be root49 - root36 in the denominator
but thats just equal to one
so the final answer becomes root7+root6
in the numerator
It should be like this I beleive
try giving the full simplified answer to the second one
Is this right
uhh in the denominator its wrong
uhh
no
$\left(\sqrt{7}-\sqrt{6}\right)\left(\sqrt{7}+\sqrt{6}\right) = \sqrt{49}-\sqrt{36} = 7-6 = 1$
How is it minus
wolfqz
multiply it
Bro don’t we go like distributive way
Like square root 7x7,7x6 and then square root 6x7 and 6x6
$\left(\sqrt{7}-\sqrt{6}\right)\left(\sqrt{7}+\sqrt{6}\right) = \sqrt{7 \times 7} + \sqrt{7 \times 6} - \sqrt{7 \times 6} - \sqrt{6 \times 6}$
wolfqz
wolfqz
this is because $-\sqrt{6} \times \sqrt{6} = -\sqrt{36}$
wolfqz
5-2 = 3
Yep yep
Huh
uhh lemme see
2root 7
oops sorry
Huh
wolfqz
I did 1x2 and 1x square root 7
Uhm
Ohhh
I did 1x2
But I didn’t do 1x7
I see
Can I have a complex question @tulip cave
wolfqz
Do you have the answer
Share
the answer or the solution?
wolfqz
hmm
Is the rest right?
uh idk
make the denominator correct
and then share solution
bc with th incorrect denominator i cant say if its right or wrong
10