#Sequences functions
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$g(n) = 5(2)^{n-1}$
wolfqz
is that correct?
yeah
so to find g of any variable a, $g(a) = 5(2)^{a-1}$
wolfqz
wolfqz
ok but what if g(-2)
just put -2 instead of n
oh $x^{-n} = \frac{1}{x^n}$
wolfqz
$g(-2) = 5(2)^{-2-1} = 5(2)^{-3} = 5\left(\frac{1}{2^3}\right) = \frac{5}{8}$
wolfqz
its 0.625
what my math techer says that incorrect......
for g(-2), 5/8 is incorrect?
yeah idk why
yeah its 0.625