Help me with this problem

[jovial ember]

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[bitter pulsar]

find 1/x first

[grand wasp]

2-√3

Actually I did the same at first

[bitter pulsar]

yep

[grand wasp]

I got my answer as 16

[bitter pulsar]

now comes the cool part

[grand wasp]

but in the book it shows 14

[rustic lichen]

wolfqz

[bitter pulsar]

that comes out to be 4

[grand wasp]

2+√3+2-√3

yes

4

[bitter pulsar]

now, remember the whole square identity?

[grand wasp]

So (4)²

Oh

OH

IDENTITY

[rustic lichen]

wolfqz

[bitter pulsar]

u forgot the extra factor 2ab, yeah

[grand wasp]

I get it now

[rustic lichen]

wolfqz

[bitter pulsar]

thats how u got 14

[grand wasp]

thanks

I need help with another problem

May i

[bitter pulsar]

sure

[grand wasp]

Question no:8

[bitter pulsar]

rationalise it

[grand wasp]

a-b√3= 2-√3/2+√3

[grand wasp]

Okay

2-√3/2+√3 × 2-√3/2-√3

idk how to do the numerator part

Which identity

[bitter pulsar]

$(a-b)^2$

[rustic lichen]

wolfqz

[grand wasp]

the denominator is 1

so

[bitter pulsar]

yep

the numerator is $(2-\sqrt{3})^2$

[rustic lichen]

wolfqz

[grand wasp]

I got the answer

Thanks

A=7
B=4

[bitter pulsar]

umm yes

you did it

yay

[grand wasp]

Tysm

I have exams on 10th

Next month

[bitter pulsar]

damn

u cna do the +close command now

[grand wasp]

I am very bad at math

[bitter pulsar]

if ur doubt is clear

[grand wasp]

Okay

Cya

+close