Work integral problem

[median cave]

I am getting work done by the gravitational force on the chain as 2mgl/9 but it should be 4mgl/9. I defined h to be the distance of com of the hanging part from the surface and found the dW in terms of h and dh and integrated it. I know I can find it easily by finding the change in PE but wanted to what went wrong. Please help.

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[median cave]

Can you write the integral i can't read it quite right

[proven nest]

whats the question

like what do u need to find

[median cave]

∫dW = -mg∫h dx (from h1 to h2) @median cave

should give you the correct work done by the gravitational force. Ensure that you have the correct limits of integration and that "h" is appropriately defined as the height above the reference point.

Good Luck

[median cave]

Work done by gravitational force

[proven nest]

to lift the hanging part of the chain?

[median cave]

To bring down the whole chain

[proven nest]

ahh

[median cave]

I did
∫dW = ∫(m/l)*(2h)*g dh (from l/6 to l/2)

[median cave]

Yes but why isn't my method working?

[median cave]

I took h to be com of hanging part then the weight is {(m/l)*2h}g so limits would be l/6 to l/2

[median cave]

umm let me think

[median cave]

Can someone help please?

[cloud torrent]

What is the context

You are giving us a whole eq without no context and data

[median cave]

We had to find the work done by gravitational force during the fall of the chain

[median cave]

@cloud torrent here's my approach but the correct answer is 4mgl/9

[median cave]

.close

[barren cosmos]

Unable to parse the channel name

[median cave]

+close