ap physics - algebra 2 problem

[quiet meadow]

A plane is flying at 200 m/s at an angle of declination of 10 degrees.
It is 5000 meters above the ground when it releases a bomb. The bomb hits its target, a truck that has been driving at a constant speed of 20 m/s. How long did the bomb fall? How far from the plane was the target when the plane released the bomb?

       So far, I've only found the initial velocities of the x and y components for the plane, but i'm not sure because Idk how the angle of declination would affect the degrees. I also have the y displacement for the plane to be 5000 m and the acceleration at -9.8 m/s^2. For the car, I only have the initial velocity at 20 m/s and the acceleration at 0 m/s^2 (not sure if that's right either)  I just don't how to approach this.

And I don't know if the bomb would be something i didn't count for as a variable because if it's being released, not thrown at the velocity of 200 m/s and angle, so would it just be in free fall?

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[ebon tendon]

well, the truck doesn't matter for how long it takes to fall down
all that matters is:
-amount of time it takes to go vertically down
and that is only affected by:
-gravity
-initial vertical velocity (seems like you already have this)
-height dropped from

[quiet meadow]

ahh okay, i thought it would count when you find the distance from the plane to the target

and also it's an angle on inclination^^ my bad

[ebon tendon]

so i would assume the plane is pointing 10° above the horizontal

so yeah if you used trig to find initial vertical then you should be good

[quiet meadow]

ah okay so after i would get a quadratic equation right?

and then the zero would be my time?

alright i did that and it's correct

but now im confused with finding the displacement for the second part 😭

[ebon tendon]

for that i would coordinate bash

say the plane started at (0,5000)

figure out at what x position it lands (different from what time it lands!!)

that's also where the truck is

[quiet meadow]

i found the x to be at 7027 m

it doesnt seem right tho

[ebon tendon]

i mean, when i calculate it i get 7028 m

so it's probably right

[quiet meadow]

ah ok

so i thought that finding that horizontal disp i use the y disp and use pthag to find that displavement between the target - bomb being released?

but the answer is incorrect

[ebon tendon]

did you find the truck's position from 35 seconds before when the bomb was released?

[quiet meadow]

it just says the truck was travelling at a constant speed of 20 m/s tho

should i find when the bomb hits the truck directly?

[ebon tendon]

i mean the plane started at (0,5000)

where did the truck start

it actually doesn't say which direction the truck is traveling so

bad problem

[quiet meadow]

i have no idea how to find it without direction

because the plane only has a y displacment of 5000 right?

but with the info given the truck is just traveling horizontally, straight line 20 m/s right?

[ebon tendon]

i would assume the truck is going in the same direction as the plane

[quiet meadow]

oh wait

so the position of the truck would be the x displacement?

[ebon tendon]

you know the bomb ends 7027 m

~35 (however long it takes to fall) seconds earlier, it would be at ...?