#Explanation Please
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A property of definite Integrals is that integrals of two functions can be added or subtracted (like in algebra) provided limits are equal, so you can subtract the two functions here and then evaluate them
Or evaluating separately doesn't make any difference
My problem is when I tried seperately or multiply them into one, i do not get 243/8 (or in -) as an answer but some other answers e.g. 99/8
what do u mean?
if i multiply the equations into one, and integrate, it does not become 243/8 (or in -), even integrating them separately wouldnt give 243/8, but when i insert the integral equation onto the calculator, it shows me 243/8 but i do not know if i am doing something wrong in the working or inserting something wrong in the calculator
because i was given some work/question where i have to multiply the equations into one and integrate it and some w/o multiplying
cause i am trying to find the bounded area
u dont multiply the integrals
if ur not sure which curve covers larger area, subtract either from the other and taking modulus of the value
like the other person said, u can add or subtract definite integrals provided they have the same limits
if i cant multiply, then why in my example which is written on paper, 3 as upperlimit, 1 as lower limit with its equation x dx - x^2 - x - 3 dx becomes x-(x^2-x-3) dx and then -x^2 + 2x + 3 dx?
r = integral curve above - curve below no?
thats not multiplying
thats subtracting the two curves
u distribute the negative sign within the quadratic curve to get -x^2+x+3
which added to x is -x^2+2x+3
yeah or alternatively u can subtract any of the curves and take the modulus so u get rid of the negative area