#Indefinite integration
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How do I reach from tan-1(tan²x) to option d?
Anyone?
$-tan^{-1}(z)=tan^{-1}(-z)$ but $\ -cos(2x) \leq 1 < 3 = tan^2(\frac{\pi}{3})$ for all x
Ludwig
what
I showed that (C) and (D) can't be the same.