The answer is a = -20, b = -40, I believe. But I don't know how to solve this.
#Logarithms Problem
raven jacinth
fallow pineBOT
The answer is a = -20, b = -40, I believe. But I don't know how to solve this.
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dark roost
i would suggest u use the base change rule that is
$log_{a}b = \frac{log_{d}b}{log_{d}a}$
raw matrixBOT
racism | #GTFOanemia
raven jacinth
i would suggest u use the base change rule that is
$log_{a}b = \frac{log_{d}b}...
both to 4?
what do i do after that
dark roost
sry had to go somewhere
im back
uh
so
the solutions u mentioned dont work
i think
they shouldnt lets check
,w -20 + (-40)log_(4)7 + 60 log_(8)14
raw matrixBOT
dark roost
$a + b \frac{\log 7}{\log 4} + 60 \frac{\log 14}{\log 8} = 0$
raw matrixBOT
racism | #GTFOanemia
dark roost
now take log 8 as a common base
and note that $\frac{3}{2} \log 4 = \log 8$
because of the power property of logs
raw matrixBOT
racism | #GTFOanemia
dark roost
Yes
dark roost
No u needed to do it to log4
To get a common denominator
This would work too but it does the same thing
dark roost
Get a common denominator
Then equate numerator to 0
did u do it @raven jacinth
$a + b \frac{\frac{3}{2} \log 7}{\log 8} + 60 \frac{\log 14}{\log 8} = 0$
raw matrixBOT
racism | #GTFOanemia
dark roost
$\frac{a \log 8}{\log 8} + b \frac{\frac{3}{2} \log 7}{\log 8} + 60 \frac{\log 14}{\log 8} = 0$
raw matrixBOT
racism | #GTFOanemia
dark roost
$a \log 8 + b \log 7^\frac{3}{2} + 60 \log 14 = 0$
raw matrixBOT
racism | #GTFOanemia
dark roost
@raven jacinth can you continue?
dark roost
ok