help

[iron kindle]

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[lucid kernel]

pi/2 + 22

or

$(\frac{2}{2})^2\frac{\pi}{2} + \frac{4(9+2)}{2}$

[ashen wave]

No Lifer?

[lucid kernel]

2/2 is radius of semicircle, 9 and 2 are the bases of the trapezium, 4 is height of trapezium

[hollow vapor]

So the answer is the formula you sent me mathematics?

[lucid kernel]

what

[hollow vapor]

look what the bot sent\

[lucid kernel]

I made the bot sent that bruv

[hollow vapor]

oh lmao

wait so what would the answer be

[lucid kernel]

refer to this if you don't know how that formula came into place

[hollow vapor]

i got pi/2 + 22

[lucid kernel]

yeah that's correct

[hollow vapor]

oh lets go

[lucid kernel]

,calc pi/2 + 22

[ashen wave]

Result:

23.570796326795

[lucid kernel]

23.57

nearest tenths huh

23.6 then

[hollow vapor]

Yeah

[lucid kernel]

yep

[hollow vapor]

What abt this one @lucid kernel

[lucid kernel]

problem solved

first, find the height of the rectangle

you already have it's length

[hollow vapor]

Yeah 14

[lucid kernel]

and you have the radius of the semicircle

[hollow vapor]

Thats the radius?

Its kinda tilted

[lucid kernel]

yeah, read the question

it's written "radius" explicitly

[hollow vapor]

I thought i would be like straight

[lucid kernel]

anyway

[lucid kernel]

doesn't have to be

[hollow vapor]

Oh ok

[lucid kernel]

now

let's tale the height of the rectangle over here as h

[hollow vapor]

Wait so that means diameter would be 6

[lucid kernel]

yes

[hollow vapor]

Ok

[lucid kernel]

so, can you get the area now?

you've derived all the required measurements

[hollow vapor]

Yeah 14x6 is 84

[lucid kernel]

yes!

and

?

[hollow vapor]

And the semicircle would be 3^2 pi

[lucid kernel]

not exactly

[hollow vapor]

9^2 pi

My bad

[lucid kernel]

you're a bit off

[hollow vapor]

Now divide it by 2

[lucid kernel]

what

[hollow vapor]

9pi

4.5 pi

[lucid kernel]

yeah 4.5 pi

and you have 84 from before

,calc 84 + (9*pi/2)

[ashen wave]

Result:

98.137166941154

[hollow vapor]

So the answer is 98.1

[lucid kernel]

yes

good job bro

[hollow vapor]

Thanks so much bro appreciate it

I have one last one

[lucid kernel]

same as the first one

trapezoid area + semicircle area

[hollow vapor]

I dont really know how to write out he formula

[lucid kernel]

you know the formula ryt?

just calculate it

and send the answer here

[hollow vapor]

No i dont

[lucid kernel]

oof

$\frac{h(b_1+b_2)}{2}$

[ashen wave]

No Lifer?

[lucid kernel]

this is for trapezium

[hollow vapor]

They prob taught me but i firgot our teacher said we had to do a grade above our level

Ok

[lucid kernel]

h is height

[hollow vapor]

Which is 10

[lucid kernel]

b1 and b2 are the bases

[lucid kernel]

yes

[hollow vapor]

Are the bases 16 and 8?

[lucid kernel]

yes!

[hollow vapor]

So 120

[lucid kernel]

yes

now for the semicircle

[hollow vapor]

Now the circle would be 8pi

[lucid kernel]

yes

[hollow vapor]

25.1

[lucid kernel]

also correct

[hollow vapor]

Now add

145.1

[lucid kernel]

,calc 120 + 8*pi

[ashen wave]

Result:

145.13274122872

[lucid kernel]

yep

gg

good job

[hollow vapor]

lets go i finished

Thanks so much bro this helped me a lot