The video that supposedly shows us how to do this solves it with a graphing calculator while we're not allowed to use one.
#How do I solve this without a graphing calculator?
hearty idol
atomic etherBOT
The video that supposedly shows us how to do this solves it with a graphing calc...
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barren hornetBOT
apex predator
hearty idol
Isn’t that just 1?
lethal basin
Isn’t that just 1?
no, why do you think it would be 1?
hearty idol
7-6/7-6
lethal basin
that's not how it works
try plugging 7 and 6 into your function h(t) and then into what I gave you
barren hornetBOT
apex predator
hearty idol
58(6) - 0.83(6)^2
Like this?
barren hornetBOT
apex predator
lethal basin
58(6) - 0.83(6)^2
Like this?
that would be h(6) yes
lethal basin
**apex predator**
so we have the distance at the end, and the distance at the beginning, so we find the distance in between by doing h(b)-h(a)
and we have the last time, and the first time, so we find the change in time by doing b-a
does that make sense?
barren hornetBOT
apex predator
hearty idol
Yes
lethal basin
ok cool
hearty idol
Thank you 🙂 I’ll be taking screenshots for future reference